Create 8 equal subnets from 192.168.1.0/24 — how many bits do you borrow, what is the new prefix/mask, and what are the 8 network addresses?

Borrow 3 bits → /27 (255.255.255.224), magic number 32; networks are .0, .32, .64, .96, .128, .160, .192, .224, each with 30 usable hosts.

Step-by-step:

1. Need 8 subnets → 2^n ≥ 8 → borrow n = 3 bits (2^3 = 8).
2. New prefix: /27; mask = 255.255.255.224 (11100000).
3. Magic number = 256 − 224 = 32 → step by 32.
4. Hosts left = 32 − 27 = 5 → 2^5 − 2 = 30 usable hosts each.

Network addresses (start at 0, add 32): .0, .32, .64, .96, .128, .160, .192, .224

Example range — 192.168.1.32/27: first host .33, last host .62, broadcast .63.

Go deeper:

• Visual Subnet Calculator (davidc.net) — split a /24 into eight /27s and confirm the .0/.32/.64… boundaries.
• ipcalc (jodies.de) — enter 192.168.1.32/27 to verify the host range and broadcast.