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Quiz Entry - updated: 2026.07.14

How is an IPv6 address structured?

128 bits, written as eight colon-separated groups of 4 hex digits; typically the first 64 bits are the network prefix and the last 64 are the interface ID.

128-bit IPv6 as eight 16-bit hex groups: the first /64 is the network prefix (/48 ISP + subnet bits), the last /64 is the interface ID.

* 128 bits = eight 16-bit hex groups — the first /64 is the network prefix (/48 from the ISP + subnet bits), the last /64 is the interface ID. *

IPv6 quadruples the address from 32 to 128 bits — an astronomically larger space, which is the whole point (no more exhaustion). To stay readable, two shorthand rules apply: drop leading zeros in each group, and replace one run of all-zero groups with ::.

2001:0db8:0000:0001:0000:0000:0000:0001
→ 2001:db8:0:1::1

Structure (the common case): a /48 block comes from the provider, leaving 16 bits to number your own subnets (48→64), and the bottom /64 is the interface ID:

Part Width Example
Network prefix (from ISP) /48 2001:db8::
Local subnet bits the 16 bits up to /64 choose per subnet
Interface ID last /64 ::1

Prefixes you'll see:

  • /48 — typical provider allocation
  • /64 — the standard subnet size, and required for SLAAC auto-configuration
  • /128 — a single host

Tip: the interface ID is often auto-derived from the MAC address (or randomised for privacy), so a host can build its own address from just the /64 prefix the router advertises.

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From Quiz: LIOS / Network Configuration | Updated: Jul 14, 2026