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Quiz Entry - updated: 2026.07.05

How is the 64-bit interface ID derived from a MAC address (EUI-64), and why isn't ARP needed?

EUI-64 inserts ff:fe into the middle of the 48-bit MAC and flips the 7th bit, yielding a 64-bit interface ID — so the link-layer address is embedded in the IPv6 address and ARP becomes unnecessary.

Insert ff:fe into the 48-bit MAC, flip the U/L bit, prepend fe80:: for the link-local.

* EUI-64 transform building a 64-bit interface ID from a MAC. *

48-bit MAC address showing the OUI/NIC split and the universal/local and individual/group bits.

* 48-bit MAC structure, source of the EUI-64 interface ID. — Inductiveload, CC BY-SA 2.5, via Wikimedia Commons. *

Worked example from a MAC of 3c:07:54:5d:40:66:

  1. Split the MAC in half and insert ff:fe in the middle → 3c:07:54:ff:fe:5d:40:66
  2. Flip the 7th bit (the universal/local bit) of the first byte: 3c = 0011 1100 → flip the marked bit → 0011 1110 = 3e — giving interface ID 3e07:54ff:fe5d:4066
  3. Prepend the link-local prefix → fe80::3e07:54ff:fe5d:4066

Because the interface ID is derived from the MAC, a node can map an IPv6 address to its link-layer address logic without the IPv4-style ARP broadcast — Neighbor Discovery (over multicast) handles resolution instead.

Tip: The tell-tale sign of an EUI-64 address is the ff:fe sitting in the middle of the interface ID. (Privacy extensions, RFC 4941, instead randomise the interface ID to avoid tracking the MAC.)

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From Quiz: INTROL / IPv6 – Das Netz der Zukunft | Updated: Jul 05, 2026