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Quiz Entry - updated: 2026.07.14

What is the fundamental interface security problem, and how do attackers exploit it?

The whole class of injection attacks is one inequality: Dec(Enc(M)) ≠ M — the receiver decodes the data into something the sender never meant, and the attacker engineers that difference on purpose.

When the round-trip is faithful (Dec(Enc(M)) = M) the interface is safe; the moment it breaks, the attacker's data acquires a second meaning on the far side:

The problem:

Sender intends M → Enc(M) → Channel → Dec(Enc(M)) → Receiver gets M' ≠ M

How attackers exploit this — all 4 conditions must hold:

Condition Meaning SQL injection example
M ≠ Dec(Enc(M)) Input transforms into something different O'Brien becomes SQL code break
M is valid for sender Input passes client-side checks Name field accepts apostrophes
Dec(Enc(M)) is valid for receiver Result is executable Database parses it as valid SQL
Actions differ Sender expects data storage, receiver executes code INSERT becomes INSERT + DROP TABLE

Why this matters: SQL injection, XSS, command injection, and URL encoding attacks ALL exploit this same pattern — data that means one thing to the sender means something different to the receiver.

From Quiz: SPRG / Security Review | Updated: Jul 14, 2026