What is the key scaling problem with symmetric cryptography?

With $n$ participants, you need $\frac{n(n-1)}{2}$ keys — the number of keys grows quadratically.

In symmetric cryptography, every pair of communicating parties needs a unique shared secret key. The formula is:

$$\text{Keys} = \frac{n(n-1)}{2}$$

The biggest challenge isn't just the number — it's key distribution: how do you securely share a secret key with someone you've never met?

Asymmetric cryptography fixes this — each person only needs one key pair (public + private), so n participants need only n key pairs. The trade-off: asymmetric operations are significantly slower.