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Question

How do you sign and verify a message with RSA, and why are signing and verifying mirror images of each other?

Answer

The signer raises the message to the secret exponent, $s = m^d \bmod N$; anyone verifies by raising the signature to the public exponent and checking $s^e \bmod N = m$. It is the same modular exponentiation run with opposite keys.

RSA sign and verify: signer computes s = m^d, verifier checks s^e = m

* Signing and verifying are the same exponentiation with opposite keys — they cancel because e·d ≡ 1 mod φ(N). *

The signer holds the RSA secret key $(p, q, d)$ and publishes $(N, e)$ with $N = p\cdot q$. Signing is just the private RSA operation:

$$s = m^d \bmod N$$

and verification is the public operation applied back:

$$s^e \equiv (m^d)^e \equiv m^{ed} \equiv m \bmod N.$$

The two undo each other because the key is built so that $e\cdot d \equiv 1 \pmod{\varphi(N)}$ — exactly the same relation that makes RSA decryption undo RSA encryption. So verifying a signature literally recomputes the message out of $s$; if the recomputed value equals the message the verifier holds, the signature is genuine.

Two practical points the raw formula hides:

  • You sign a hash, not the raw document. In practice $m$ is $h(\text{message})$ — a fixed-size digest — so any length of contract fits inside $\mathbb{Z}_N$ and one exponentiation binds the whole document.
  • Signing is the "reverse" of encrypting only for RSA. Encryption is $c = m^e$ (public exponent), signing is $s = m^d$ (secret exponent) — the operations look symmetric here, which is convenient but is precisely what the existential-forgery attack exploits (see the next card). Most other signature schemes (DSA, Schnorr) deliberately make signing and verifying different operations to avoid that.

Go deeper:

Adi Shamir, co-inventor of RSA (the others are Ron Rivest and Leonard Adleman)
Adi Shamir, co-inventor of RSA (the others are Ron Rivest and Leonard Adleman)
Ira Abramov from Even Yehuda, Israel · CC BY-SA 2.0 · Wikimedia Commons
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